A satellite revolves round Earth at an altitude of

PHYSICS · Single correct · A Level · Physics · Fields and their consequences · Fields and their consequences

Problem

A satellite revolves round Earth at an altitude of 700 km700\,\text{km}. Take G=6.67×10−11 N m2 ⁣/kg2G = 6.67\times10^{-11}\,\text{N m}^{2}\!\text{/kg}^{2}, M ⁣E=5.97×1024 kgM_{\!E}=5.97\times10^{24}\,\text{kg} and R ⁣E=6.4×106 mR_{\!E}=6.4\times10^{6}\,\text{m}. The orbital period of the satellite is closest to (a) 150 min150\,\text{min} (b) 24 h24\,\text{h} (c) 94 min94\,\text{min} (d) 85 min85\,\text{min}

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