The gas-phase decomposition of in the presence of a platinum surface obeys the…

CHEMISTRY · Subjective · AP · Chemistry · Kinetics · Kinetics

Problem

The gas-phase decomposition of NO2\text{NO}_2 in the presence of a platinum surface obeys the experimental rate law rate =k[NO2]2[Pt(s)]= k[\text{NO}_2]^2[\text{Pt(s)}]. Two mechanisms have been proposed: Mechanism 1 Step 1 (fast equilibrium) Pt(s)+NO2  ⇌  NO2 ⁣ ⁣− ⁣ ⁣Pt\quad \text{Pt(s)} + \text{NO}_2 \;\rightleftharpoons\; \text{NO}_2\!\!-\!\!\text{Pt} Step 2 (slow) NO2 ⁣ ⁣− ⁣ ⁣Pt+NO2⟶NO+NO3 ⁣ ⁣− ⁣ ⁣Pt\quad \text{NO}_2\!\!-\!\!\text{Pt} + \text{NO}_2 \longrightarrow \text{NO} + \text{NO}_3\!\!-\!\!\text{Pt} Step 3 (fast) NO3 ⁣ ⁣− ⁣ ⁣Pt⟶NO+12O2+Pt(s)\quad \text{NO}_3\!\!-\!\!\text{Pt} \longrightarrow \text{NO} + \tfrac{1}{2}\text{O}_2 + \text{Pt(s)} Mechanism 2 Step 1 (slow) 2 NO2⟶N2O4\quad 2\,\text{NO}_2 \longrightarrow \text{N}_2\text{O}_4 Step 2 (fast) N2O4+Pt(s)⟶NO+NO3 ⁣ ⁣− ⁣ ⁣Pt\quad \text{N}_2\text{O}_4 + \text{Pt(s)} \longrightarrow \text{NO} + \text{NO}_3\!\!-\!\!\text{Pt} Step 3 (fast) NO3 ⁣ ⁣− ⁣ ⁣Pt⟶NO+12O2+Pt(s)\quad \text{NO}_3\!\!-\!\!\text{Pt} \longrightarrow \text{NO} + \tfrac{1}{2}\text{O}_2 + \text{Pt(s)} Which mechanism (1 or 2) is consistent with the rate law? State the mechanism number and give one-sentence reasoning.

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