For , is 176 at 1240 K. The for the change is equal to…

CHEMISTRY · Single correct · CBSE · Chemistry · Thermodynamics · Thermodynamics

Problem

ΔH\Delta H for CaCO3(s)→CaO(s)+CO2(g)\text{CaCO}_3(\text{s}) \rightarrow \text{CaO}(\text{s}) + \text{CO}_2(\text{g}), is 176 kJ mol−1\text{kJ mol}^{-1} at 1240 K. The ΔU\Delta U for the change is equal to : (A) 160 kJ (B) 165.6 kJ (C) 186.3 kJ (D) 180.0 kJ

Related theory

Browse the problem library