A straight conductor of length is suspended freely so that it lies along the…

MATHEMATICS · Multi-part · CBSE · Mathematics · Vector Algebra · Vector Algebra

Problem

A straight conductor of length 0.30 m0.30\,\text{m} is suspended freely so that it lies along the North–South direction. It carries a current of 5 A5\,\text{A} from South to North. The region contains a uniform horizontal magnetic field of 0.8 T0.8\,\text{T} directed from East to West. (i) Calculate the magnitude of the force exerted on the conductor. (ii) Predict the direction in which the conductor will initially move. (iii) The magnetic field is now reversed while keeping the current direction unchanged. What will happen to the direction of the force? Explain your answer.

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