To determine the enthalpy change for a student uses the following steps

CHEMISTRY · Single correct · A Level · Chemistry · Energetics · Energetics

Problem

To determine the enthalpy change for 2NO(g)+O2(g)→2NO2(g)2\text{NO}(g) + \text{O}_2(g) \rightarrow 2\text{NO}_2(g) a student uses the following steps. Step 1: N2(g)+O2(g)→2NO(g)ΔH1=+182 kJ\text{N}_2(g) + \text{O}_2(g) \rightarrow 2\text{NO}(g) \qquad \Delta H_1 = +182\,\text{kJ} Step 2: 2NO2(g)→N2(g)+2O2(g)ΔH2=+114 kJ2\text{NO}_2(g) \rightarrow \text{N}_2(g) + 2\text{O}_2(g) \qquad \Delta H_2 = +114\,\text{kJ} The student adds Steps 1 and 2 to obtain the target equation and calculates ΔHcalc=+296 kJ\Delta H_{\text{calc}} = +296\,\text{kJ}. Which of the following statements correctly describes the student’s error and the corrected value of ΔH\Delta H? (a) ΔH=+296 kJ\Delta H = +296\,\text{kJ} because the sign of Step 2 was not changed after reversal. (b) Step 2 was written in the wrong direction; reversing it changes its sign, giving ΔH=−296 kJ\Delta H = -296\,\text{kJ}. (c) ΔH=−68 kJ\Delta H = -68\,\text{kJ}, the value obtained when Step 1 is reversed instead of Step 2. (d) Doubling Step 1 to match the 2NO2\text{NO} in the target gives ΔH=+478 kJ\Delta H = +478\,\text{kJ}.

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