If a 100 mL solution of 0.1M HBr is titrated using a very concentrated solution of NaOH, then the conductivity (specific conductance) of this solution at the equivalence point will be (assume volume change is negligible due to addition of NaOH). Report your answer after multiplying it with 10 in S m−1.
Given λNa+∘=8×10−3S m2mol−1, λBr−∘=4×10−3S m2mol−1.
(a) 6
(b) 12
(c) 15
(d) 24