A soap bubble is expanding so that its radius (in centimeters) changes with time…

MATHEMATICS · Multi-part · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

A soap bubble is expanding so that its radius r(t)r(t) (in centimeters) changes with time according to the model drdt=0.015t+0.010,t≥0, \displaystyle \frac{dr}{dt}=0.015t+0.010, \quad t\ge 0, where tt is measured in seconds. Let V(t)=43πr(t)3V(t)=\dfrac{4}{3}\pi r(t)^3 denote the volume of the bubble and S(t)=4πr(t)2S(t)=4\pi r(t)^2 its surface area. Define the efficiency ratio of the bubble by E(t)=V(t)S(t).E(t)=\dfrac{V(t)}{S(t)}. Answer the following questions. (a) Obtain an explicit expression for dEdt\dfrac{dE}{dt} in terms of rr and drdt\dfrac{dr}{dt}. Simplify your result completely. (b) At t=4 st=4\text{ s} the radius is r=1.16 cmr=1.16\text{ cm}. Compute dEdt\dfrac{dE}{dt} at this instant and state the units of your answer. (c) Determine the exact time t>0t>0 at which the efficiency ratio E(t)E(t) attains its maximum value. Justify that the value you obtain indeed corresponds to a maximum. (d) Physically interpret what it means for dEdt\dfrac{dE}{dt} to be zero for the expanding bubble.

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