The height (in meters) of a projectile is given by for

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

The height (in meters) of a projectile is given by h(t)=−4.9t2+24t+1h(t)=-4.9t^{2}+24t+1 for 0≤t≤50\le t\le5, where tt is time in seconds. At what time does the projectile reach its greatest height during this interval? (a) t=1.2 st=1.2\text{ s} (b) t=5.0 st=5.0\text{ s} (c) t≈2.45 st\approx2.45\text{ s} (d) t≈4.9 st\approx4.9\text{ s}

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