Find out the energy of H atom in first excitation state

CHEMISTRY · Subjective · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

Find out the energy of H atom in first excitation state. The value of permittivity factor 4πϵ0=1.11264×10−10 C2 N−1 m−24\pi\epsilon_0 = 1.11264 \times 10^{-10} \text{ C}^2 \text{ N}^{-1} \text{ m}^{-2} .

Related theory

Browse the problem library