An aqueous solution is prepared by mixing 0.100 mol of H2SO4(aq) with exactly twice…

CHEMISTRY · Multi-part · AP · Chemistry · Chemical Reactions · Chemical Reactions

Problem

An aqueous solution is prepared by mixing 0.100 mol of H2SO4(aq) with exactly twice that amount of NaOH(aq). The neutralization reaction is represented by the balanced equation H2SO4(aq)+2 NaOH(aq)→Na2SO4(aq)+2 H2O(l)\text{H}_2\text{SO}_4(aq) + 2\,\text{NaOH}(aq) \to \text{Na}_2\text{SO}_4(aq) + 2\,\text{H}_2\text{O}(l) Assume that all species remain uniformly dispersed in a sufficiently large volume of water and that water molecules are omitted from the particulate drawing unless explicitly requested. (1) Part 1: (a) Determine the number of formula units or discrete ions of each species that must appear in a particulate-level snapshot representing TWO complete reaction cycles (i.e., twice the coefficients in the balanced equation). List spectator ions separately from species that undergo chemical change. (2) Part 2: (b) Draw and label a particulate-level diagram that depicts the system immediately after the reaction has gone to completion. Represent Na+\text{Na}^+ as small orange spheres, SO42−\text{SO}_4^{2-} as a tetrahedral cluster of four red O atoms around one yellow S atom, and omit the bulk water. Clearly reflect the quantities calculated in part (a). (3) Part 3: (c) Explain how your diagram illustrates the role of spectator ions in this reaction and why water molecules may be legitimately omitted from the aqueous representation in parts (a) and (b).

Related theory

Browse the problem library