For each case below

PHYSICS · Multi-part · CBSE · Physics · Thermodynamics · Thermodynamics

Problem

For each case below, use the given entropy changes to decide whether the process is reversible or irreversible: (a) ΔSsys=+5 J K−1\Delta S_{\text{sys}} = +5\,\text{J K}^{-1}, ΔSsurr=−5 J K−1\Delta S_{\text{surr}} = -5\,\text{J K}^{-1} (b) ΔSsys=+2 J K−1\Delta S_{\text{sys}} = +2\,\text{J K}^{-1}, ΔSsurr=−1 J K−1\Delta S_{\text{surr}} = -1\,\text{J K}^{-1}

Related theory

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