In a circle, two chords and are equidistant from the centre . The length of is and…

MATHEMATICS · Multi-part · CBSE · Mathematics · Circles · Circles

Problem

In a circle, two chords ABAB and CDCD are equidistant from the centre OO. The length of ABAB is (3x−4) cm(3x - 4)\,\text{cm} and the length of CDCD is (x+8) cm(x + 8)\,\text{cm}. A third chord EFEF is equal in length to CDCD and subtends a central angle of (2y+20)∘(2y + 20)^\circ. The chord ABAB subtends a central angle of 100∘100^\circ. (i) Form two algebraic equations in xx and yy using the given information. (ii) Solve the equations to find the values of xx and yy. (iii) Determine the common length of the three chords and the angle subtended by chord EFEF at any point on the circumference of the circle.

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