One gram of water ( ) becomes of steam when boiled at a constant pressure of ( )

PHYSICS · Multi-part · CBSE · Physics · Thermodynamics · Thermodynamics

Problem

One gram of water (

1\,\text{cm}^3

) becomes

1671\,\text{cm}^3

of steam when boiled at a constant pressure of

1\,\text{atm}

(

1.013\times10^5\,\text{Pa}

). The heat of vaporization at this pressure is

L_v=2.256\times10^6\,\text{J kg}^{-1}

. Compute: (a) The work done by the water when it vaporizes. (b) Its increase in internal energy.