The function defined by f(x) = cases ( x^2 + e^ 1 2-x )^ -1 , & x 2 k, & x = 2 cases…

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

The function defined by

f(x) = \begin{cases} \left( x^2 + e^{\frac{1}{2-x}} \right)^{-1}, & x \neq 2 \\ k, & x = 2 \end{cases}

from right at the point

x = 2

, then

k

is equal to (a) 0 (b)

1/4

(c)

-1/4

(d) None of these