A box with a square base and no top is to be constructed

MATHEMATICS · Multi-part · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

A box with a square base and no top is to be constructed. Exactly 48 m248\text{ m}^2 of material is available for the four sides and the base. Let ss be the length of one side of the square base (in meters), let hh be the height of the box (in meters), and let V(s)V(s) be the volume (in cubic meters) written solely as a function of ss for s>0s>0. (a) Derive an expression for V(s)V(s) in terms of ss using the surface–area constraint. State the permissible domain of ss. (b) Determine the value of ss that maximizes VV and calculate the corresponding height hh. Show complete calculus justification. (c) Verify that the critical point obtained in part (b) yields a maximum by applying a second–derivative test or an equivalent argument based on concavity. (d) Provide the exact maximum volume of the box, simplified and expressed with correct units.

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