If the shortest distance between the lines and is units

MATHEMATICS · Subjective · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

If the shortest distance between the lines

\frac{x-3}{3} = \frac{y-8}{-1} = \frac{z-3}{1}

and

\frac{x+3}{-3} = \frac{y+7}{2} = \frac{z-6}{2}

is

\lambda\sqrt{30}

units, then the value of

\lambda

is .....

Related theory

Browse the problem library