Consider the improper integral

MATHEMATICS · Single correct · AP · Calculus BC · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

Consider the improper integral ∫031(x−1)2 dx\displaystyle\int_{0}^{3}\frac{1}{(x-1)^2}\,dx. Which of the following is true? (a) The integral diverges because the integrand has a vertical asymptote at x=1x=1, so no finite value exists. (b) The integral converges and equals 11. (c) The integral diverges because the integrand is unbounded at x=0x=0. (d) The integral converges and equals 32\dfrac{3}{2}.

Related theory

Browse the problem library