The freezing point of 0.02 mole fraction of acetic acid in benzene is

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Problem

The freezing point of 0.02 mole fraction of acetic acid in benzene is 277.4 K277.4 \text{ K} . Acetic acid exists partly as dimer. Calculate the equilibrium constant for dimerisation. Freezing point of benzene is 278.4 K278.4 \text{ K} and heat of fusion of benzene is 10.042 kJ mol−110.042 \text{ kJ mol}^{-1} . Assume molarity and molality same.

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