The corrosion of iron can proceed through several intermediate solid oxides

CHEMISTRY · Multi-part · A Level · Chemistry · Thermodynamics · Thermodynamics

Problem

The corrosion of iron can proceed through several intermediate solid oxides. Three reactions measured at 298 K298\,\text{K} are listed below: Overall Reaction: 3 Fe(s)+2 O2(g)→Fe3O4(s)3\,Fe(s) + 2\,O_2(g) \to Fe_3O_4(s)  ΔSoverall∘=−545.8 J mol−1 K−1\Delta S^\circ_{\text{overall}} = -545.8\,\text{J mol}^{-1}\,\text{K}^{-1} Step 1: Fe(s)+0.5 O2(g)→FeO(s)Fe(s) + 0.5\,O_2(g) \to FeO(s)  ΔS1∘=−143.5 J mol−1 K−1\Delta S^\circ_{1} = -143.5\,\text{J mol}^{-1}\,\text{K}^{-1} Step 2: 3 FeO(s)+0.5 O2(g)→Fe3O4(s)3\,FeO(s) + 0.5\,O_2(g) \to Fe_3O_4(s)  ΔS2∘=  ?\Delta S^\circ_{2} = \; ? Step 2 involves the further oxidation of w\"ustite (FeOFeO) to magnetite (Fe3O4Fe_3O_4). Use the information above to answer the following. (a) Calculate the standard entropy change ΔS2∘\Delta S^\circ_{2} for Step 2. (b) State whether the sign of ΔS2∘\Delta S^\circ_{2} is expected, considering the change in the amount of gaseous reactant, and justify your answer. (c) Compute the average entropy change per mole of O2O_2 consumed in Step 2, and comment on how this compares to the value for Step 1.

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