For the curve defined parametrically by and

MATHEMATICS · Single correct · A Level · Mathematics · Differentiation · Differentiation

Problem

For the curve defined parametrically by x=3t2+1x=3t^{2}+1 and y=2t−5y=2t-5, find the equation of the tangent at the point corresponding to t=2t=2. (a) 6x−y−19=06x-y-19=0 (b) x+6y−19=0x+6y-19=0 (c) x−6y−19=0x-6y-19=0 (d) x−6y+19=0x-6y+19=0

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