The circle and hyperbola intersect at the points A and B

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The circle x2+y2−8x=0x^2 + y^2 - 8x = 0 and hyperbola x29−y24=1\frac{x^2}{9} - \frac{y^2}{4} = 1 intersect at the points A and B. Equation of the circle with AB as its diameter is (1) x2+y2−12x+24=0x^2 + y^2 - 12x + 24 = 0 (2) x2+y2+12x+24=0x^2 + y^2 + 12x + 24 = 0 (3) x2+y2+24x−12=0x^2 + y^2 + 24x - 12 = 0 (4) x2+y2−24x−12=0x^2 + y^2 - 24x - 12 = 0

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