Define F(x)= cases x, & - x<0

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Define F(x)={sin⁡x,−π≤x<0,cx+d,0≤x<2,5−x,2≤x≤5,F(x)=\begin{cases}\sin x, & -\pi\le x<0,\\ cx+d, & 0\le x<2,\\ \sqrt{5-x}, & 2\le x\le 5,\end{cases} where cc and dd are constants. (1) Determine the values of cc and dd that make FF continuous on the closed interval [−π,5][-\pi,5]. (2) With the constants found in part (a), justify that there exists at least one value pp in [−π,5][-\pi,5] for which F(p)=1F(p)=1. Clearly identify an interval on which your argument is valid. (3) Prove that, with the same constants, the equation F(x)=0.5F(x)=0.5 has at least two distinct solutions in [−π,5][-\pi,5]. Indicate separate intervals containing each solution and justify your claim.

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