For the spiral with

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

For the spiral r=aθr=a\theta with a>0a>0, which expression gives the exact length of the curve from θ=0\theta=0 to θ=2π\theta=2\pi? (a) a[2π4π2+1+12ln⁡ ⁣(2π+4π2+1)]a\left[2\pi\sqrt{4\pi^{2}+1}+\dfrac12\ln\!\left(2\pi+\sqrt{4\pi^{2}+1}\right)\right] (b) a[π4π2+1+12ln⁡ ⁣(2π+4π2+1)]a\left[\pi\sqrt{4\pi^{2}+1}+\dfrac12\ln\!\left(2\pi+\sqrt{4\pi^{2}+1}\right)\right] (c) a[π4π2+1+ln⁡ ⁣(2π+4π2+1)]a\left[\pi\sqrt{4\pi^{2}+1}+\ln\!\left(2\pi+\sqrt{4\pi^{2}+1}\right)\right] (d) a[π4π2+1]a\left[\pi\sqrt{4\pi^{2}+1}\right]

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