Take Earth’s mass as and its radius as

PHYSICS · Subjective · CBSE · Physics · Gravitation · Gravitation

Problem

Take Earth’s mass as M⊕=5.97×1024 kgM_{\oplus}=5.97\times10^{24}\,\text{kg} and its radius as R⊕=6.37×106 mR_{\oplus}=6.37\times10^{6}\,\text{m}. The universal gravitational constant is G=6.67×10−11 N m2 kg−2G=6.67\times10^{-11}\,\text{N\,m}^{2}\,\text{kg}^{-2}. (i) Calculate the magnitude of Earth’s gravitational field intensity at the surface. (ii) At what altitude hh above the Earth’s surface will the gravitational field intensity become one-fourth of the surface value obtained in part (i)? Express hh both in metres and in kilometres. (iii) How does the result of part (ii) compare with the Earth–Moon distance (3.84×108 m3.84\times10^{8}\,\text{m})? Comment briefly.

Related theory

Browse the problem library