For the reaction

CHEMISTRY · Single correct · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

ERP∘E_{RP}^\circ for the reaction, TeO32− (1M)+3H2O (l)+4e⟶Te (s)+6OH− (aq)\text{TeO}_3^{2-} \text{ (1M)} + 3\text{H}_2\text{O (l)} + 4e \longrightarrow \text{Te (s)} + 6\text{OH}^- \text{ (aq)} is −0.57 V-0.57 \text{ V} . Calculate the potential of pH = 12. (1) −0.17 V-0.17 \text{ V} (2) −0.21 V-0.21 \text{ V} (3) −0.39 V-0.39 \text{ V} (4) −0.747 V-0.747 \text{ V}

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