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CHEMISTRY · Subjective · A Level · Chemistry · Thermodynamics · Thermodynamics
Problem Use the data below, all at 298 K, to calculate the missing standard entropy change.
(a) CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( ℓ ) \text{CH}_{4}(g)+2\,\text{O}_{2}(g) \rightarrow \text{CO}_{2}(g)+2\,\text{H}_{2}\text{O}(\ell) CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( ℓ ) Δ S ∘ = − 242 J mol − 1 K − 1 \Delta S^{\circ}= -242\;\text{J mol}^{-1}\text{K}^{-1} Δ S ∘ = − 242 J mol − 1 K − 1
(b) CO ( g ) + 1 2 O 2 ( g ) → CO 2 ( g ) \text{CO}(g)+\dfrac{1}{2}\,\text{O}_{2}(g) \rightarrow \text{CO}_{2}(g) CO ( g ) + 2 1 O 2 ( g ) → CO 2 ( g ) Δ S ∘ = − 174 J mol − 1 K − 1 \Delta S^{\circ}= -174\;\text{J mol}^{-1}\text{K}^{-1} Δ S ∘ = − 174 J mol − 1 K − 1
(c) CH 4 ( g ) + 3 2 O 2 ( g ) → CO ( g ) + 2 H 2 O ( ℓ ) \text{CH}_{4}(g)+\dfrac{3}{2}\,\text{O}_{2}(g) \rightarrow \text{CO}(g)+2\,\text{H}_{2}\text{O}(\ell) CH 4 ( g ) + 2 3 O 2 ( g ) → CO ( g ) + 2 H 2 O ( ℓ ) Δ S ∘ = ? \Delta S^{\circ}=\, ? Δ S ∘ = ?
Calculate Δ S ∘ \Delta S^{\circ} Δ S ∘ for reaction (c).
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