A network consists of five resistors arranged as follows:
• R1=2Ω and R2=4Ω are connected in series.
• Their combination is connected in parallel with R3=6Ω.
• The result of the above is then connected in series with R4=3Ω.
• Finally, this entire arrangement is connected across a 18V battery of negligible internal resistance together with a resistor R5=5Ω in series.
Answer the following:
(i) Find the single equivalent resistance of the complete circuit.
(ii) Calculate the total current drawn from the battery.
(iii) Determine the current through and the potential difference across each of the five resistors.