The equation can be written as:

MATHEMATICS · Single correct · AP · AP Precalculus · Exponential and Logarithmic Functions · Exponential and Logarithmic Functions

Problem

The equation 2=log⁡x+1(y+1)2 = \log_{x+1}(y + 1) can be written as: (A) y=2log⁡x+1−2y = \frac{2}{\log_{x+1}} - 2 (B) y=(x+1)2−1y = (x + 1)^2 - 1 (C) y=2(x+1)−1y = 2(x + 1) - 1 (D) y=log⁡x+12−1y = \log_{x+1} 2 - 1

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