A mosquito flying at collides head-on with a bus moving at in the opposite direction

PHYSICS · Single correct · CBSE · Physics · Force and Laws of Motion · Force and Laws of Motion

Problem

A 0.005 kg0.005\,\text{kg} mosquito flying at 2 m/s2\,\text{m/s} collides head-on with a 10 000 kg10\,000\,\text{kg} bus moving at 15 m/s15\,\text{m/s} in the opposite direction. During the very brief collision, how do the magnitudes of the forces compare? Let FbmF_{bm} be the force exerted by the bus on the mosquito and FmbF_{mb} the force exerted by the mosquito on the bus. (a) Fbm=−FmbF_{bm} = -F_{mb} (b) Fbm=FmbF_{bm} = F_{mb} (c) Fbm>FmbF_{bm} > F_{mb} (d) FbmFmb=mbmm\dfrac{F_{bm}}{F_{mb}} = \dfrac{m_b}{m_m}

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