A nuclide decays into with decay constant

PHYSICS · Single correct · A Level · Physics · Nuclear physics · Nuclear physics

Problem

A nuclide XX decays into YY with decay constant λX\lambda_X. Nuclide YY subsequently decays into a stable product with decay constant λY\lambda_Y. If λX≪λY\lambda_X\ll \lambda_Y, which statement best describes how the activity of YY changes with time? (a) The activity of YY rises to a maximum and then decays at approximately the fast rate λY\lambda_Y, largely independent of nuclide XX. (b) The activity of YY quickly reaches a constant value equal to (λX/λY)(\lambda_X/\lambda_Y) times the activity of XX and then remains steady. (c) The activity of YY rises to a maximum and then decays at approximately the same slow rate as nuclide XX. (d) Because λX\lambda_X is so small, the production of YY is negligible, so its activity stays near zero at all times.

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