A proton enters a sequence of two parallel-plate regions

PHYSICS · Single correct · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance

Problem

A proton enters a sequence of two parallel-plate regions. First, it passes through a region where the electric potential drops by 2.00 kV, and immediately afterward it enters a region where the potential rises by 1.50 kV. If the proton’s speed just before the first region is 4.0×105 m ⁣⋅ ⁣s−14.0\times10^{5}\,\text{m}\!\cdot\!\text{s}^{-1}, what is its speed after emerging from the second region? (Proton mass mp=1.67×10−27 kgm_p = 1.67\times10^{-27}\,\text{kg}, charge magnitude e=1.6×10−19 Ce = 1.6\times10^{-19}\,\text{C}.) (a) 2.5×105 m ⁣⋅ ⁣s−12.5\times10^{5}\,\text{m}\!\cdot\!\text{s}^{-1} (b) 3.1×105 m ⁣⋅ ⁣s−13.1\times10^{5}\,\text{m}\!\cdot\!\text{s}^{-1} (c) 5.1×105 m ⁣⋅ ⁣s−15.1\times10^{5}\,\text{m}\!\cdot\!\text{s}^{-1} (d) 7.3×105 m ⁣⋅ ⁣s−17.3\times10^{5}\,\text{m}\!\cdot\!\text{s}^{-1}

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