A Level

MATHEMATICS · Single correct · A Level · Mathematics · Trigonometry · Trigonometry

Problem

Solve

\tan 2\theta = \sqrt{3}

for

\theta \in (-\pi/2,\,\pi/2)

. (a)

\theta = -\dfrac{\pi}{3},\;\dfrac{\pi}{3}

(b)

\theta = -\dfrac{\pi}{3},\;\dfrac{\pi}{6}

(c)

\theta = -\dfrac{\pi}{6},\;\dfrac{\pi}{3}

(d)

\theta = -\dfrac{\pi}{6},\;\dfrac{\pi}{6}