The emf of cell is 0.788 V

CHEMISTRY · Subjective · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

The emf of cell Ag∣AgI(s),0.05 M KI∥0.05 M AgNO3∣Ag\text{Ag} \mid \text{AgI}(s), 0.05 \text{ M KI} \parallel 0.05 \text{ M AgNO}_3 \mid \text{Ag} is 0.788 V. Calculate solubility product of AgI.

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