Statement-1 Let _r = vmatrix (r-1)! & n! (r-1)^2 & (n!)^2 (r-1)^3 & 3r^2 - 2n vmatrix

MATHEMATICS · Subjective · CBSE · Mathematics · Determinants · Determinants

Problem

Statement-1 LetΔr=∣(r−1)!n!(r−1)2(n!)2(r−1)33r2−2n∣, then ∏r=2n+1Δr=0.\Delta_r = \begin{vmatrix} (r-1)! & n! \\ (r-1)^2 & (n!)^2 \\ (r-1)^3 & 3r^2 - 2n \end{vmatrix}, \text{ then } \prod_{r=2}^{n+1} \Delta_r = 0. Statement-2 ∏r=1n+1Δr=Δ2⋅Δ3⋅Δ4⋯Δn+1\prod_{r=1}^{n+1} \Delta_r = \Delta_2 \cdot \Delta_3 \cdot \Delta_4 \cdots \Delta_{n+1}

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