A rectangular billboard must cover an advertising area of

MATHEMATICS · Multi-part · A Level · Mathematics · Differentiation · Differentiation

Problem

A rectangular billboard must cover an advertising area of 30 m230\,\text{m}^2. The material used for the frame along the perimeter costs 2525 per meter, while the special vinyl covering the face incurs a cost that grows with width according to c(w)=50e0.05wc(w)=50e^{0.05w} dollars per square meter, where ww is the width (in meters) of the billboard. The height of the billboard is denoted hh (in meters). (a) Write a formula for the total cost C(w)C(w) of constructing the billboard in terms of ww only. (b) Compute C′(w)C'(w) and simplify. (c) Find all critical widths w>0w>0 that satisfy C′(w)=0C'(w)=0. (d) Use a second--derivative test or sign analysis to justify which critical width minimizes the total cost. (e) Determine the corresponding height and calculate the minimal total cost to the nearest dollar.

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