On the interval the function is given by h(x)= cases 3x+2, & 0 x 2, (x-4)^ 2 , & 2< x 5

MATHEMATICS · Subjective · CBSE · Mathematics · Relations and Functions · Relations and Functions

Problem

On the interval [0,5][0,5] the function hh is given by h(x)={3x+2,0≤x≤2,(x−4)2,2<x≤5.h(x)= \begin{cases} 3x+2, & 0\le x\le 2,\\ (x-4)^{2}, & 2< x\le 5. \end{cases} Determine the minimum value of hh on [0,5][0,5].

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