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MATHEMATICS · Subjective · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions
Problem If A = 1 1 cot − 1 ( 1 1 ) + 1 2 cot − 1 ( 1 2 ) + 1 3 cot − 1 ( 1 3 ) A = \frac{1}{1} \cot^{-1}\left(\frac{1}{1}\right) + \frac{1}{2} \cot^{-1}\left(\frac{1}{2}\right) + \frac{1}{3} \cot^{-1}\left(\frac{1}{3}\right) A = 1 1 cot − 1 ( 1 1 ) + 2 1 cot − 1 ( 2 1 ) + 3 1 cot − 1 ( 3 1 ) B = 1 cot − 1 ( 1 ) + 2 cot − 1 ( 2 ) + 3 cot − 1 ( 3 ) B = 1 \cot^{-1}(1) + 2 \cot^{-1}(2) + 3 \cot^{-1}(3) B = 1 cot − 1 ( 1 ) + 2 cot − 1 ( 2 ) + 3 cot − 1 ( 3 ) ∣ B − A ∣ |B - A| ∣ B − A ∣ a π b + c d cot − 1 ( 3 ) \frac{a\pi}{b} + \frac{c}{d} \cot^{-1}(3) b aπ + d c cot − 1 ( 3 ) a , b , c , d ∈ N a, b, c, d \in \mathbb{N} a , b , c , d ∈ N ( b − a − c − d ) (b - a - c - d) ( b − a − c − d ) Browse the problem library