For a particle the displacement–time relation is (in metres

MATHEMATICS · Multi-part · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

For a particle the displacement–time relation is x(t)=t3−6t2+9tx(t) = t^{3} - 6t^{2} + 9t (in metres, tt in seconds). (i) Find the instants when the particle reverses its direction of motion. (ii) Determine the displacement of the particle between t=0t = 0 and t=6 st = 6\,\text{s}.

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