Which of the following best explains why the relation for the arc–length formula is…

MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

Which of the following best explains why the relation dsdθ=r\dfrac{ds}{d\theta}=r for the arc–length formula s=rθs=r\theta is valid only when the angle θ\theta is measured in radians? (a) Because radians are appropriate only for very small angles, so the approximation s≈rθs\approx r\theta is treated as exact, giving a constant slope of rr. (b) Because in radian measure θ\theta is expressed in the same length units as ss, causing the units to cancel in ds/dθds/d\theta and leaving the constant rr. (c) Because a radian is defined as the ratio of an arc’s length to its radius, θ\theta has no units, so ddθ(θ)=1\dfrac{d}{d\theta}(\theta)=1, making dsdθ=r\dfrac{ds}{d\theta}=r. (d) Because radians effectively set π=180\pi=180, removing the conversion factor π/180\pi/180 that appears with degrees and leaving dsdθ=r\dfrac{ds}{d\theta}=r.

Related theory

Browse the problem library