The image of the line in the plane is the line

MATHEMATICS · Single correct · IB Diploma Programme · Mathematics: Analysis and Approaches · Geometry and Trigonometry · Geometry and Trigonometry

Problem

The image of the line

\frac{x-1}{3}=\frac{y-3}{1}=\frac{z-4}{-5}

in the plane

2x-y+z+3=0

is the line (1)

\frac{x+3}{3}=\frac{y-5}{1}=\frac{z-2}{-5}

(2)

\frac{x+3}{-3}=\frac{y-5}{-1}=\frac{z+2}{5}

(3)

\frac{x-3}{3}=\frac{y+5}{1}=\frac{z-2}{-5}

(4)

\frac{x-3}{-3}=\frac{y+5}{-1}=\frac{z-2}{5}