The locus of a point equidistant from two given points whose position vectors are and…

MATHEMATICS · Single correct · CBSE · Mathematics · Vector Algebra · Vector Algebra

Problem

The locus of a point equidistant from two given points whose position vectors are a\mathbf{a} and b\mathbf{b} is equal to (1) [r−12(a+b)]⋅(a+b)=0[ \mathbf{r} - \frac{1}{2}(\mathbf{a} + \mathbf{b}) ] \cdot (\mathbf{a} + \mathbf{b}) = 0 (2) [r−12(a+b)]⋅(a−b)=0[ \mathbf{r} - \frac{1}{2}(\mathbf{a} + \mathbf{b}) ] \cdot (\mathbf{a} - \mathbf{b}) = 0 (3) [r−12(a+b)]⋅a=0[ \mathbf{r} - \frac{1}{2}(\mathbf{a} + \mathbf{b}) ] \cdot \mathbf{a} = 0 (4) [r−(a+b)]⋅b=0[\mathbf{r} - (\mathbf{a} + \mathbf{b})] \cdot \mathbf{b} = 0

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