Define by g(x)= cases x+1,& x<0

MATHEMATICS · Single correct · CBSE · Mathematics · Relations and Functions · Relations and Functions

Problem

Define

g:\mathbb{R}\to\mathbb{R}

g(x)=\begin{cases} x+1,& x<0,\\ x^{2}+1,& x\ge 0. \end{cases}

The function

g

is: (a) onto but not one–one (b) both one–one and onto (c) one–one but not onto (d) neither one–one nor onto