Determine whether the series converges or diverges.

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Determine whether the series S=∑n=1∞3n2+1\displaystyle S=\sum_{n=1}^{\infty}\frac{3}{n^{2}+1} converges or diverges. (a) SS diverges because its terms behave like 3n\dfrac{3}{n} for large nn, a divergent pp\,-series. (b) SS converges because its terms are eventually less than 3n2\dfrac{3}{n^{2}}, a convergent pp\,-series. (c) SS converges because its terms form a geometric sequence with ratio less than 11. (d) SS diverges because the denominator grows more slowly than n2n^{2} for large nn.

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