During the algebraic derivation of the work–energy theorem

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

During the algebraic derivation of the work–energy theorem, the element of work is written as dW=ma dxdW = m a\,dx and then converted to dW=mv dvdW = m v\,dv. Which mathematical substitution justifies this conversion? (a) Using a=v dxdva = v\,\dfrac{dx}{dv} (b) Using a=vdvdxa = v\dfrac{dv}{dx} only (c) Using a=dvdxa = \dfrac{dv}{dx} only (d) Using a=dvdta = \dfrac{dv}{dt} and dt=v dxdt = v\,dx

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