Evaluate (3.20 10^ 6 )-(7.50 10^ 5 ) (4.0 10^ -2 )(2.5 10^ 3 ) and express the answer…

PHYSICS · Subjective · CBSE · Physics · Units and Measurements · Units and Measurements

Problem

Evaluate (3.20×106)−(7.50×105)(4.0×10−2)(2.5×103)\frac{(3.20\times10^{6})-(7.50\times10^{5})}{(4.0\times10^{-2})(2.5\times10^{3})} and express the answer to three significant figures in the form A×106A\times10^{6}. State the numerical value of AA.

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