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The equation of the circle passing through and and having the minimum radius is:
MATHEMATICS · Single correct · GCSE · Mathematics · Graphs · Graphs
Problem
The equation of the circle passing through
(
2
,
0
)
(2,0)
(
2
,
0
)
and
(
0
,
4
)
(0,4)
(
0
,
4
)
and having the minimum radius is: (1)
x
2
+
y
2
=
20
x^2+y^2=20
x
2
+
y
2
=
20
(2)
x
2
+
y
2
−
2
x
−
4
y
=
0
x^2+y^2-2x-4y=0
x
2
+
y
2
−
2
x
−
4
y
=
0
(3)
(
x
2
+
y
2
−
4
)
+
λ
(
x
2
+
y
2
−
16
)
=
0
(x^2+y^2-4)+\lambda(x^2+y^2-16)=0
(
x
2
+
y
2
−
4
)
+
λ
(
x
2
+
y
2
−
16
)
=
0
(4) None of the above
Related theory
Distance and Section in the Plane
Circle (Standard Equation)
Conic Sections
Equation of a Circle
Coordinate Geometry
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