The expression is equal to

MATHEMATICS · Single correct · A Level · Mathematics · Trigonometry · Trigonometry

Problem

The expression (a+b+c)(b+c−a)(c+a−b)(a+b−c)4b2c2\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4b^2c^2} is equal to (1) cos⁡2A\cos^2 A (2) sin⁡2A\sin^2 A (3) cos⁡Acos⁡Bcos⁡C\cos A\cos B\cos C (4) None of these

Related theory

Browse the problem library