Statement I is differentiable at

MATHEMATICS · Subjective · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

Statement I f(x)=∣x∣sin⁡xf(x) = |x| \sin x is differentiable at x=0x = 0 . Statement II If g(x)g(x) is not differentiable at x=ax = a and h(x)h(x) is differentiable at x=ax = a , then g(x)⋅h(x)g(x) \cdot h(x) cannot be differentiable at x=ax = a .

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