Suppose and are functions having second derivatives and everywhere

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

Suppose ff and gg are functions having second derivatives f′′f'' and g′′g'' everywhere. If f(x)g(x)=1f(x)g(x)=1 for all xx and f′f' and g′g' are never zero, then f′′(x)f′(x)−g′′(x)g′(x)\frac{f''(x)}{f'(x)}-\frac{g''(x)}{g'(x)} equals. (a) −2f′(x)f(x)-\frac{2f'(x)}{f(x)} (b) −2g′(x)g(x)-\frac{2g'(x)}{g(x)} (c) −f′(x)f(x)-\frac{f'(x)}{f(x)} (d) 2f′(x)f(x)\frac{2f'(x)}{f(x)}

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