The graph of

MATHEMATICS · Multi-part · AP · Calculus AB · Analytical Applications of Differentiation · Analytical Applications of Differentiation

Problem

The graph of y=f′(x)y=f'(x), the first derivative of a twice-differentiable function ff, consists of two straight-line segments and one semicircular arc. The graph intersects the xx-axis at the points x=−2x=-2 and x=1x=1. From x=−4x=-4 to x=−2x=-2, f′(x)f'(x) is the line segment joining (−4,3)(-4,3) to (−2,0)(-2,0). From x=−2x=-2 to x=1x=1, f′(x)f'(x) coincides with the upper half of the circle centered at (−12,0)( -\tfrac{1}{2},0) with radius 32\tfrac{3}{2}. From x=1x=1 to x=3x=3, f′(x)f'(x) is the line segment joining (1,0)(1,0) to (3,2)(3,2). Assume ff is defined and twice differentiable for all xx with f(−4)=2f(-4)=2. (a) For each interval determined by the xx-intercepts of f′(x)f'(x), determine whether f′(x)f'(x) is positive or negative. Justify your conclusions with reference to the given graph description. (b) Using your results from part (a), state the open intervals on (−4,3)(-4,3) where ff is increasing and the open intervals where ff is decreasing. (c) Identify each relative extremum of ff on the interval (−4,3)(-4,3), specifying the xx-coordinate and whether the extremum is a maximum or a minimum. Justify your answers. (d) On the interval [−4,3][-4,3], determine the absolute maximum value of ff. Clearly indicate how you reach your conclusion, including consideration of endpoints.

Related theory

Browse the problem library